n6/11=83/n

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Solution for n6/11=83/n equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

(n^6)/11 = 83/n // - 83/n

(n^6)/11-(83/n) = 0

(n^6)/11-83*n^-1 = 0

1/11*n^6-83*n^-1 = 0

n^-1*(1/11*n^7-83) = 0

1/11*n^7 = 83 // : 1/11

n^7 = 913

n^7 = 913 // ^ 1/7

n = 913^(1/7)

1/n = 0

1*n^-1 = 0 // : 1

n^-1 = 0

n należy do O

n = 913^(1/7)

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