n2=491

Solution for n2=491 equation:

n2=491

We move all terms to the left:

n2-(491)=0

We add all the numbers together, and all the variables

n^2-491=0

a = 1; b = 0; c = -491;
Δ = b2-4ac
Δ = 02-4·1·(-491)
Δ = 1964
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1964}=\sqrt{4*491}=\sqrt{4}*\sqrt{491}=2\sqrt{491}$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{491}}{2*1}=\frac{0-2\sqrt{491}}{2}
=-\frac{2\sqrt{491}}{2}
=-\sqrt{491}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{491}}{2*1}=\frac{0+2\sqrt{491}}{2}
=\frac{2\sqrt{491}}{2}
=\sqrt{491}
$