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n2-n-306=0
We add all the numbers together, and all the variables
n^2-1n-306=0
a = 1; b = -1; c = -306;
Δ = b2-4ac
Δ = -12-4·1·(-306)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-35}{2*1}=\frac{-34}{2} =-17 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+35}{2*1}=\frac{36}{2} =18 $
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