n2-n-121=0

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Solution for n2-n-121=0 equation:



n2-n-121=0
We add all the numbers together, and all the variables
n^2-1n-121=0
a = 1; b = -1; c = -121;
Δ = b2-4ac
Δ = -12-4·1·(-121)
Δ = 485
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{485}}{2*1}=\frac{1-\sqrt{485}}{2} $
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{485}}{2*1}=\frac{1+\sqrt{485}}{2} $

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