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n2-2n-3=5000
We move all terms to the left:
n2-2n-3-(5000)=0
We add all the numbers together, and all the variables
n^2-2n-5003=0
a = 1; b = -2; c = -5003;
Δ = b2-4ac
Δ = -22-4·1·(-5003)
Δ = 20016
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{20016}=\sqrt{144*139}=\sqrt{144}*\sqrt{139}=12\sqrt{139}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-12\sqrt{139}}{2*1}=\frac{2-12\sqrt{139}}{2} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+12\sqrt{139}}{2*1}=\frac{2+12\sqrt{139}}{2} $
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