n/(n-3)=2/3

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Solution for n/(n-3)=2/3 equation: 


D( n )

n-3 = 0

n-3 = 0

n-3 = 0

n-3 = 0 // + 3

n = 3

n in (-oo:3) U (3:+oo)

n/(n-3) = 2/3 // - 2/3

n/(n-3)-(2/3) = 0

n/(n-3)-2/3 = 0

(3*n)/(3*(n-3))+(-2*(n-3))/(3*(n-3)) = 0

3*n-2*(n-3) = 0

n+6 = 0

(n+6)/(3*(n-3)) = 0

(n+6)/(3*(n-3)) = 0 // * 3*(n-3)

n+6 = 0

n+6 = 0 // - 6

n = -6

n = -6

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