n.2/n=n/128

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Solution for n.2/n=n/128 equation: 



n.2/n=n/128

We move all terms to the left:

n.2/n-(n/128)=0



Domain of the equation: n!=0

n∈R



We add all the numbers together, and all the variables

n.2/n-(+n/128)=0

We get rid of parentheses

n.2/n-n/128=0

We calculate fractions


(-1n^2)/128n+(n.2*128)/128n=0

We add all the numbers together, and all the variables

(-1n^2)/128n+(+n.2*128)/128n=0

We multiply all the terms by the denominator


(-1n^2)+(+n.2*128)=0

We get rid of parentheses

-1n^2+n.2*128=0

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