n-6(9)=3(n-2)

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Solution for n-6(9)=3(n-2) equation: 



n-6(9)=3(n-2)

We move all terms to the left:

n-6(9)-(3(n-2))=0



We calculate terms in parentheses: -(3(n-2)), so:

3(n-2)

We multiply parentheses

3n-6

Back to the equation:

-(3n-6)



We get rid of parentheses

n-3n+6-69=0

We add all the numbers together, and all the variables

-2n-63=0

We move all terms containing n to the left, all other terms to the right

-2n=63

n=63/-2

n=-31+1/2

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