n-3n-2=(n+1)

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Solution for n-3n-2=(n+1) equation: 



n-3n-2=(n+1)

We move all terms to the left:

n-3n-2-((n+1))=0

We add all the numbers together, and all the variables

-2n-((n+1))-2=0



We calculate terms in parentheses: -((n+1)), so:

(n+1)

We get rid of parentheses

n+1

Back to the equation:

-(n+1)



We get rid of parentheses

-2n-n-1-2=0

We add all the numbers together, and all the variables

-3n-3=0

We move all terms containing n to the left, all other terms to the right

-3n=3

n=3/-3

n=-1

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