n-3(n-2)=6+n

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Solution for n-3(n-2)=6+n equation: 



n-3(n-2)=6+n

We move all terms to the left:

n-3(n-2)-(6+n)=0

We add all the numbers together, and all the variables

n-3(n-2)-(n+6)=0

We multiply parentheses

n-3n-(n+6)+6=0

We get rid of parentheses

n-3n-n-6+6=0

We add all the numbers together, and all the variables

-3n=0

n=0/-3

n=0

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