n-1=-3(1-n)

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Solution for n-1=-3(1-n) equation: 



n-1=-3(1-n)

We move all terms to the left:

n-1-(-3(1-n))=0

We add all the numbers together, and all the variables

n-(-3(-1n+1))-1=0



We calculate terms in parentheses: -(-3(-1n+1)), so:

-3(-1n+1)

We multiply parentheses

3n-3

Back to the equation:

-(3n-3)



We get rid of parentheses

n-3n+3-1=0

We add all the numbers together, and all the variables

-2n+2=0

We move all terms containing n to the left, all other terms to the right

-2n=-2

n=-2/-2

n=1

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