n-(2/n)=(7/3)

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Solution for n-(2/n)=(7/3) equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

n-(2/n) = 7/3 // - 7/3

n-(2/n)-(7/3) = 0

n-2*n^-1-7/3 = 0

1*n^1-2*n^-1-7/3*n^0 = 0

(1*n^2-7/3*n^1-2*n^0)/(n^1) = 0 // * n^2

n^1*(1*n^2-7/3*n^1-2*n^0) = 0

n^1

n^2+(-7/3)*n-2 = 0

n^2+(-7/3)*n-2 = 0

DELTA = (-7/3)^2-(-2*1*4)

DELTA = 121/9

DELTA > 0

n = ((121/9)^(1/2)-(-7/3))/(1*2) or n = (-(-7/3)-(121/9)^(1/2))/(1*2)

n = 3 or n = -2/3

n in { -2/3, 3} 

n in { -2/3, 3 }

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