n+40/8=5(n-15)/15

Solution for n+40/8=5(n-15)/15 equation:

n+40/8=5(n-15)/15

We move all terms to the left:

n+40/8-(5(n-15)/15)=0

We add all the numbers together, and all the variables

n-(5(n-15)/15)+5=0

We multiply all the terms by the denominator


n*15)-(5(n-15)+5*15)=0

We add all the numbers together, and all the variables

n*15)-(5(n-15)=0

Wy multiply elements

15n^2=0

a = 15; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·15·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{0}{30}=0$