n+3=2(n+2)+3n

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Solution for n+3=2(n+2)+3n equation:



n+3=2(n+2)+3n
We move all terms to the left:
n+3-(2(n+2)+3n)=0
We calculate terms in parentheses: -(2(n+2)+3n), so:
2(n+2)+3n
We add all the numbers together, and all the variables
3n+2(n+2)
We multiply parentheses
3n+2n+4
We add all the numbers together, and all the variables
5n+4
Back to the equation:
-(5n+4)
We get rid of parentheses
n-5n-4+3=0
We add all the numbers together, and all the variables
-4n-1=0
We move all terms containing n to the left, all other terms to the right
-4n=1
n=1/-4
n=-1/4

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