n+3/n+4-n-4/n-3

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Solution for n+3/n+4-n-4/n-3 equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

n-n+3/n-(4/n)-3+4 = 0

n-n+3/n-4*n^-1-3+4 = 0

-1*n^-1 = -1 // : -1

n^-1 = 1

-1 < 0

1/(n^1) = 1 // * n^1

1 = 1*n^1 // : 1

1 = n^1

n = 1

n = 1

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