n+2=2n-(n-2)

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Solution for n+2=2n-(n-2) equation: 



n+2=2n-(n-2)

We move all terms to the left:

n+2-(2n-(n-2))=0



We calculate terms in parentheses: -(2n-(n-2)), so:

2n-(n-2)

We get rid of parentheses

2n-n+2

We add all the numbers together, and all the variables

n+2

Back to the equation:

-(n+2)



We get rid of parentheses

n-n-2+2=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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