n+2=1/3(3n=6)

Solution for n+2=1/3(3n=6) equation:

n+2=1/3(3n=6)

We move all terms to the left:

n+2-(1/3(3n)=0


Domain of the equation: 33n+2!=0

We move all terms containing n to the left, all other terms to the right

33n!=-2

n!=-2/33

n!=-2/33

n∈R


We multiply all the terms by the denominator


n*33n+2-(1=0

We add all the numbers together, and all the variables

n*33n=0

Wy multiply elements

33n^2=0

a = 33; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·33·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{0}{66}=0$