n+2=1-(4-2n)

Solution for n+2=1-(4-2n) equation:

n+2=1-(4-2n)

We move all terms to the left:

n+2-(1-(4-2n))=0

We add all the numbers together, and all the variables

n-(1-(-2n+4))+2=0


We calculate terms in parentheses: -(1-(-2n+4)), so:

1-(-2n+4)

determiningTheFunctionDomain
-(-2n+4)+1

We get rid of parentheses

2n-4+1

We add all the numbers together, and all the variables

2n-3

Back to the equation:

-(2n-3)


We get rid of parentheses

n-2n+3+2=0

We add all the numbers together, and all the variables

-1n+5=0

We move all terms containing n to the left, all other terms to the right

-n=-5

n=-5/-1

n=+5