n+2(n+2)=4(n+1)-5

Solution for n+2(n+2)=4(n+1)-5 equation:

Simplifying
n + 2(n + 2) = 4(n + 1) + -5

Reorder the terms:
n + 2(2 + n) = 4(n + 1) + -5
n + (2 * 2 + n * 2) = 4(n + 1) + -5
n + (4 + 2n) = 4(n + 1) + -5

Reorder the terms:
4 + n + 2n = 4(n + 1) + -5

Combine like terms: n + 2n = 3n
4 + 3n = 4(n + 1) + -5

Reorder the terms:
4 + 3n = 4(1 + n) + -5
4 + 3n = (1 * 4 + n * 4) + -5
4 + 3n = (4 + 4n) + -5

Reorder the terms:
4 + 3n = 4 + -5 + 4n

Combine like terms: 4 + -5 = -1
4 + 3n = -1 + 4n

Solving
4 + 3n = -1 + 4n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-4n' to each side of the equation.
4 + 3n + -4n = -1 + 4n + -4n

Combine like terms: 3n + -4n = -1n
4 + -1n = -1 + 4n + -4n

Combine like terms: 4n + -4n = 0
4 + -1n = -1 + 0
4 + -1n = -1

Add '-4' to each side of the equation.
4 + -4 + -1n = -1 + -4

Combine like terms: 4 + -4 = 0
0 + -1n = -1 + -4
-1n = -1 + -4

Combine like terms: -1 + -4 = -5
-1n = -5

Divide each side by '-1'.
n = 5

Simplifying
n = 5