n+2(n+1)+3(n+2)=134

Solution for n+2(n+1)+3(n+2)=134 equation:

Simplifying
n + 2(n + 1) + 3(n + 2) = 134

Reorder the terms:
n + 2(1 + n) + 3(n + 2) = 134
n + (1 * 2 + n * 2) + 3(n + 2) = 134
n + (2 + 2n) + 3(n + 2) = 134

Reorder the terms:
n + 2 + 2n + 3(2 + n) = 134
n + 2 + 2n + (2 * 3 + n * 3) = 134
n + 2 + 2n + (6 + 3n) = 134

Reorder the terms:
2 + 6 + n + 2n + 3n = 134

Combine like terms: 2 + 6 = 8
8 + n + 2n + 3n = 134

Combine like terms: n + 2n = 3n
8 + 3n + 3n = 134

Combine like terms: 3n + 3n = 6n
8 + 6n = 134

Solving
8 + 6n = 134

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -8 + 6n = 134 + -8

Combine like terms: 8 + -8 = 0
0 + 6n = 134 + -8
6n = 134 + -8

Combine like terms: 134 + -8 = 126
6n = 126

Divide each side by '6'.
n = 21

Simplifying
n = 21