n+0.6n=n+0.1n2

Solution for n+0.6n=n+0.1n2 equation:

n+0.6n=n+0.1n^2

We move all terms to the left:

n+0.6n-(n+0.1n^2)=0

We add all the numbers together, and all the variables

-(n+0.1n^2)+1.6n=0

We get rid of parentheses

-0.1n^2-n+1.6n=0

We add all the numbers together, and all the variables

-0.1n^2+0.6n=0

a = -0.1; b = 0.6; c = 0;
Δ = b2-4ac
Δ = 0.62-4·(-0.1)·0
Δ = 0.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.6)-\sqrt{0.36}}{2*-0.1}=\frac{-0.6-\sqrt{0.36}}{-0.2}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.6)+\sqrt{0.36}}{2*-0.1}=\frac{-0.6+\sqrt{0.36}}{-0.2}
$