n+(n-2)+(n-4)=

Solution for n+(n-2)+(n-4)= equation:

Simplifying
n + (n + -2) + (n + -4) = 0

Reorder the terms:
n + (-2 + n) + (n + -4) = 0

Remove parenthesis around (-2 + n)
n + -2 + n + (n + -4) = 0

Reorder the terms:
n + -2 + n + (-4 + n) = 0

Remove parenthesis around (-4 + n)
n + -2 + n + -4 + n = 0

Reorder the terms:
-2 + -4 + n + n + n = 0

Combine like terms: -2 + -4 = -6
-6 + n + n + n = 0

Combine like terms: n + n = 2n
-6 + 2n + n = 0

Combine like terms: 2n + n = 3n
-6 + 3n = 0

Solving
-6 + 3n = 0

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '6' to each side of the equation.
-6 + 6 + 3n = 0 + 6

Combine like terms: -6 + 6 = 0
0 + 3n = 0 + 6
3n = 0 + 6

Combine like terms: 0 + 6 = 6
3n = 6

Divide each side by '3'.
n = 2

Simplifying
n = 2