n+(n+4)=132

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Solution for n+(n+4)=132 equation:


Simplifying
n + (n + 4) = 132

Reorder the terms:
n + (4 + n) = 132

Remove parenthesis around (4 + n)
n + 4 + n = 132

Reorder the terms:
4 + n + n = 132

Combine like terms: n + n = 2n
4 + 2n = 132

Solving
4 + 2n = 132

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + 2n = 132 + -4

Combine like terms: 4 + -4 = 0
0 + 2n = 132 + -4
2n = 132 + -4

Combine like terms: 132 + -4 = 128
2n = 128

Divide each side by '2'.
n = 64

Simplifying
n = 64

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