n+(n+2)+(n+4)=3(n+4)+15

Solution for n+(n+2)+(n+4)=3(n+4)+15 equation:

Simplifying
n + (n + 2) + (n + 4) = 3(n + 4) + 15

Reorder the terms:
n + (2 + n) + (n + 4) = 3(n + 4) + 15

Remove parenthesis around (2 + n)
n + 2 + n + (n + 4) = 3(n + 4) + 15

Reorder the terms:
n + 2 + n + (4 + n) = 3(n + 4) + 15

Remove parenthesis around (4 + n)
n + 2 + n + 4 + n = 3(n + 4) + 15

Reorder the terms:
2 + 4 + n + n + n = 3(n + 4) + 15

Combine like terms: 2 + 4 = 6
6 + n + n + n = 3(n + 4) + 15

Combine like terms: n + n = 2n
6 + 2n + n = 3(n + 4) + 15

Combine like terms: 2n + n = 3n
6 + 3n = 3(n + 4) + 15

Reorder the terms:
6 + 3n = 3(4 + n) + 15
6 + 3n = (4 * 3 + n * 3) + 15
6 + 3n = (12 + 3n) + 15

Reorder the terms:
6 + 3n = 12 + 15 + 3n

Combine like terms: 12 + 15 = 27
6 + 3n = 27 + 3n

Add '-3n' to each side of the equation.
6 + 3n + -3n = 27 + 3n + -3n

Combine like terms: 3n + -3n = 0
6 + 0 = 27 + 3n + -3n
6 = 27 + 3n + -3n

Combine like terms: 3n + -3n = 0
6 = 27 + 0
6 = 27

Solving
6 = 27

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.