n+(n+2)+(n+4)=141

Solution for n+(n+2)+(n+4)=141 equation:

Simplifying
n + (n + 2) + (n + 4) = 141

Reorder the terms:
n + (2 + n) + (n + 4) = 141

Remove parenthesis around (2 + n)
n + 2 + n + (n + 4) = 141

Reorder the terms:
n + 2 + n + (4 + n) = 141

Remove parenthesis around (4 + n)
n + 2 + n + 4 + n = 141

Reorder the terms:
2 + 4 + n + n + n = 141

Combine like terms: 2 + 4 = 6
6 + n + n + n = 141

Combine like terms: n + n = 2n
6 + 2n + n = 141

Combine like terms: 2n + n = 3n
6 + 3n = 141

Solving
6 + 3n = 141

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + 3n = 141 + -6

Combine like terms: 6 + -6 = 0
0 + 3n = 141 + -6
3n = 141 + -6

Combine like terms: 141 + -6 = 135
3n = 135

Divide each side by '3'.
n = 45

Simplifying
n = 45