n+(n+1)+(n+2)=63

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Solution for n+(n+1)+(n+2)=63 equation: 



n+(n+1)+(n+2)=63

We move all terms to the left:

n+(n+1)+(n+2)-(63)=0

We get rid of parentheses

n+n+n+1+2-63=0

We add all the numbers together, and all the variables

3n-60=0

We move all terms containing n to the left, all other terms to the right

3n=60

n=60/3

n=20

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