n+(4n-3)/9-5=(2n+1)/3

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Solution for n+(4n-3)/9-5=(2n+1)/3 equation: 


n in (-oo:+oo)

(4*n-3)/9+n-5 = (2*n+1)/3 // - (2*n+1)/3

(4*n-3)/9-((2*n+1)/3)+n-5 = 0

(4*n-3)/9+(-1*(2*n+1))/3+n-5 = 0

(3*(4*n-3))/(3*9)+(-1*9*(2*n+1))/(3*9)+(3*9*n)/(3*9)+(-5*3*9)/(3*9) = 0

3*(4*n-3)-1*9*(2*n+1)+3*9*n-5*3*9 = 0

27*n-6*n-135-18 = 0

21*n-135-18 = 0

21*n-153 = 0

(21*n-153)/(3*9) = 0

(21*n-153)/(3*9) = 0 // * 3*9

21*n-153 = 0

21*n-153 = 0 // + 153

21*n = 153 // : 21

n = 153/21

n = 51/7

n = 51/7

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