n(n2-6)=n2-n

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Solution for n(n2-6)=n2-n equation: 



n(n2-6)=n2-n

We move all terms to the left:

n(n2-6)-(n2-n)=0

We add all the numbers together, and all the variables

n(+n^2-6)-(+n^2-1n)=0

We multiply parentheses

n^3-(+n^2-1n)-6n=0

We get rid of parentheses

n^3-n^2+1n-6n=0

We do not support enpression: n^3

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