n(n-4)=-32/7

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Solution for n(n-4)=-32/7 equation: 



n(n-4)=-32/7

We move all terms to the left:

n(n-4)-(-32/7)=0

We multiply parentheses

n^2-4n-(-32/7)=0

We get rid of parentheses

n^2-4n+32/7=0

We multiply all the terms by the denominator


n^2*7-4n*7+32=0

Wy multiply elements

7n^2-28n+32=0

a = 7; b = -28; c = +32;
Δ = b2-4ac
Δ = -282-4·7·32
Δ = -112
Delta is less than zero, so there is no solution for the equation

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