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n(n-1)=650
We move all terms to the left:
n(n-1)-(650)=0
We multiply parentheses
n^2-1n-650=0
a = 1; b = -1; c = -650;
Δ = b2-4ac
Δ = -12-4·1·(-650)
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2601}=51$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-51}{2*1}=\frac{-50}{2} =-25 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+51}{2*1}=\frac{52}{2} =26 $
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