n(n+2)=0.01584

Solution for n(n+2)=0.01584 equation:

n(n+2)=0.01584

We move all terms to the left:

n(n+2)-(0.01584)=0

We add all the numbers together, and all the variables

n(n+2)-0.01584=0

We multiply parentheses

n^2+2n-0.01584=0

a = 1; b = 2; c = -0.01584;
Δ = b2-4ac
Δ = 22-4·1·(-0.01584)
Δ = 4.06336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-\sqrt{4.06336}}{2*1}=\frac{-2-\sqrt{4.06336}}{2}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+\sqrt{4.06336}}{2*1}=\frac{-2+\sqrt{4.06336}}{2}
$