n(n+1)(n+2)=1

Solution for n(n+1)(n+2)=1 equation:

Simplifying
n(n + 1)(n + 2) = 1

Reorder the terms:
n(1 + n)(n + 2) = 1

Reorder the terms:
n(1 + n)(2 + n) = 1

Multiply (1 + n) * (2 + n)
n(1(2 + n) + n(2 + n)) = 1
n((2 * 1 + n * 1) + n(2 + n)) = 1
n((2 + 1n) + n(2 + n)) = 1
n(2 + 1n + (2 * n + n * n)) = 1
n(2 + 1n + (2n + n2)) = 1

Combine like terms: 1n + 2n = 3n
n(2 + 3n + n2) = 1
(2 * n + 3n * n + n2 * n) = 1
(2n + 3n2 + n3) = 1

Solving
2n + 3n2 + n3 = 1

Solving for variable 'n'.

Reorder the terms:
-1 + 2n + 3n2 + n3 = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + 2n + 3n2 + n3 = 0

The solution to this equation could not be determined.