n(180(n-2))=n(360+108n)

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Solution for n(180(n-2))=n(360+108n) equation: 



n(180(n-2))=n(360+108n)

We move all terms to the left:

n(180(n-2))-(n(360+108n))=0

We add all the numbers together, and all the variables

n(180(n-2))-(n(108n+360))=0



We calculate terms in parentheses: -(n(108n+360)), so:

n(108n+360)

We multiply parentheses

108n^2+360n

Back to the equation:

-(108n^2+360n)



We get rid of parentheses

-108n^2+n(180(n-2))-360n=0

We add all the numbers together, and all the variables

-108n^2-360n+n(180(n-2))=0

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