n^-2/3=9

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Solution for n^-2/3=9 equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

(n^-2)/3 = 9 // - 9

(n^-2)/3-9 = 0

1/3*n^-2 = 9 // : 1/3

n^-2 = 27

-2 < 0

1/(n^2) = 27 // * n^2

1 = 27*n^2 // : 27

1/27 = n^2

n^2 = 1/27 // ^ 1/2

abs(n) = (1/27)^(1/2)

n = (1/27)^(1/2) or n = -(1/27)^(1/2)

n in { (1/27)^(1/2), -(1/27)^(1/2) }

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