mod(X-1)+mod(2X-3)=2

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Solution for mod(X-1)+mod(2X-3)=2 equation:


Simplifying
mod(X + -1) + mod(2X + -3) = 2

Reorder the terms:
dmo(-1 + X) + mod(2X + -3) = 2
(-1 * dmo + X * dmo) + mod(2X + -3) = 2
(-1dmo + dmoX) + mod(2X + -3) = 2

Reorder the terms:
-1dmo + dmoX + dmo(-3 + 2X) = 2
-1dmo + dmoX + (-3 * dmo + 2X * dmo) = 2
-1dmo + dmoX + (-3dmo + 2dmoX) = 2

Reorder the terms:
-1dmo + -3dmo + dmoX + 2dmoX = 2

Combine like terms: -1dmo + -3dmo = -4dmo
-4dmo + dmoX + 2dmoX = 2

Combine like terms: dmoX + 2dmoX = 3dmoX
-4dmo + 3dmoX = 2

Solving
-4dmo + 3dmoX = 2

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Reorder the terms:
-2 + -4dmo + 3dmoX = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + -4dmo + 3dmoX = 0

The solution to this equation could not be determined.

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