m2+m-28=0

Solution for m2+m-28=0 equation:

m2+m-28=0

We add all the numbers together, and all the variables

m^2+m-28=0

a = 1; b = 1; c = -28;
Δ = b2-4ac
Δ = 12-4·1·(-28)
Δ = 113
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{113}}{2*1}=\frac{-1-\sqrt{113}}{2}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{113}}{2*1}=\frac{-1+\sqrt{113}}{2}
$