m/5m+2(m+1)=23*

Solution for m/5m+2(m+1)=23* equation:

m/5m+2(m+1)=23*

We move all terms to the left:

m/5m+2(m+1)-(23*)=0


Domain of the equation: 5m!=0

m!=0/5

m!=0

m∈R


We add all the numbers together, and all the variables

m/5m+2(m+1)-0=0

We add all the numbers together, and all the variables

m/5m+2(m+1)=0

We multiply parentheses

m/5m+2m+2=0

We multiply all the terms by the denominator


m+2m*5m+2*5m=0

Wy multiply elements

10m^2+m+10m=0

We add all the numbers together, and all the variables

10m^2+11m=0

a = 10; b = 11; c = 0;
Δ = b2-4ac
Δ = 112-4·10·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-11}{2*10}=\frac{-22}{20}
=-1+1/10
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+11}{2*10}=\frac{0}{20}
=0
$