m/4(2m-1)=2m+35

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Solution for m/4(2m-1)=2m+35 equation:



m/4(2m-1)=2m+35
We move all terms to the left:
m/4(2m-1)-(2m+35)=0
Domain of the equation: 4(2m-1)!=0
m∈R
We get rid of parentheses
m/4(2m-1)-2m-35=0
We multiply all the terms by the denominator
m-2m*4(2m-1)-35*4(2m-1)=0
Wy multiply elements
-8m^2(2-140m(2+m=0

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