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m/2m-7=-5m+14*
We move all terms to the left:
m/2m-7-(-5m+14*)=0
Domain of the equation: 2m!=0We add all the numbers together, and all the variables
m!=0/2
m!=0
m∈R
m/2m-(-5m)-7=0
We get rid of parentheses
m/2m+5m-7=0
We multiply all the terms by the denominator
m+5m*2m-7*2m=0
Wy multiply elements
10m^2+m-14m=0
We add all the numbers together, and all the variables
10m^2-13m=0
a = 10; b = -13; c = 0;
Δ = b2-4ac
Δ = -132-4·10·0
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-13}{2*10}=\frac{0}{20} =0 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+13}{2*10}=\frac{26}{20} =1+3/10 $
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