m-9/m=8

Solution for m-9/m=8 equation:

m-9/m=8

We move all terms to the left:

m-9/m-(8)=0


Domain of the equation: m!=0

m∈R


We multiply all the terms by the denominator


m*m-8*m-9=0

We add all the numbers together, and all the variables

-8m+m*m-9=0

Wy multiply elements

m^2-8m-9=0

a = 1; b = -8; c = -9;
Δ = b2-4ac
Δ = -82-4·1·(-9)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-10}{2*1}=\frac{-2}{2}
=-1
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+10}{2*1}=\frac{18}{2}
=9
$