m-2/5-m/3=(m+1)/2

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Solution for m-2/5-m/3=(m+1)/2 equation: 


m in (-oo:+oo)

m-(m/3)-(2/5) = (m+1)/2 // - (m+1)/2

m-((m+1)/2)-(m/3)-(2/5) = 0

m-((m+1)/2)-(m/3)-2/5 = 0

(-1*(m+1))/2+m-m/3-2/5 = 0

(-1*3*5*(m+1))/(2*3*5)+(2*3*5*m)/(2*3*5)+(2*5*(-m))/(2*3*5)+(-2*2*3)/(2*3*5) = 0

2*3*5*m-1*3*5*(m+1)+2*5*(-m)-2*2*3 = 0

15*m-10*m-15-12 = 0

5*m-15-12 = 0

5*m-27 = 0

(5*m-27)/(2*3*5) = 0

(5*m-27)/(2*3*5) = 0 // * 2*3*5

5*m-27 = 0

5*m-27 = 0 // + 27

5*m = 27 // : 5

m = 27/5

m = 27/5

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