m+3(2m+2)=27

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Solution for m+3(2m+2)=27 equation: 



m+3(2m+2)=27

We move all terms to the left:

m+3(2m+2)-(27)=0

We multiply parentheses

m+6m+6-27=0

We add all the numbers together, and all the variables

7m-21=0

We move all terms containing m to the left, all other terms to the right

7m=21

m=21/7

m=3

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