m+2m+(2m+16)+(2m-10)=150

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Solution for m+2m+(2m+16)+(2m-10)=150 equation: 



m+2m+(2m+16)+(2m-10)=150

We move all terms to the left:

m+2m+(2m+16)+(2m-10)-(150)=0

We add all the numbers together, and all the variables

3m+(2m+16)+(2m-10)-150=0

We get rid of parentheses

3m+2m+2m+16-10-150=0

We add all the numbers together, and all the variables

7m-144=0

We move all terms containing m to the left, all other terms to the right

7m=144

m=144/7

m=20+4/7

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