m(m+3)+26=(m+4)(m+5)

Solution for m(m+3)+26=(m+4)(m+5) equation:

m(m+3)+26=(m+4)(m+5)

We move all terms to the left:

m(m+3)+26-((m+4)(m+5))=0

We multiply parentheses

m^2+3m-((m+4)(m+5))+26=0

We multiply parentheses ..

m^2-((+m^2+5m+4m+20))+3m+26=0


We calculate terms in parentheses: -((+m^2+5m+4m+20)), so:

(+m^2+5m+4m+20)

We get rid of parentheses

m^2+5m+4m+20

We add all the numbers together, and all the variables

m^2+9m+20

Back to the equation:

-(m^2+9m+20)


We add all the numbers together, and all the variables

m^2+3m-(m^2+9m+20)+26=0

We get rid of parentheses

m^2-m^2+3m-9m-20+26=0

We add all the numbers together, and all the variables

-6m+6=0

We move all terms containing m to the left, all other terms to the right

-6m=-6

m=-6/-6

m=1