logx+1(a+x-6)=2

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Solution for logx+1(a+x-6)=2 equation:


Simplifying
logx + 1(a + x + -6) = 2

Reorder the terms:
glox + 1(-6 + a + x) = 2
glox + (-6 * 1 + a * 1 + x * 1) = 2
glox + (-6 + 1a + 1x) = 2

Reorder the terms:
-6 + 1a + glox + 1x = 2

Solving
-6 + 1a + glox + 1x = 2

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '6' to each side of the equation.
-6 + 1a + glox + 6 + 1x = 2 + 6

Reorder the terms:
-6 + 6 + 1a + glox + 1x = 2 + 6

Combine like terms: -6 + 6 = 0
0 + 1a + glox + 1x = 2 + 6
1a + glox + 1x = 2 + 6

Combine like terms: 2 + 6 = 8
1a + glox + 1x = 8

Add '-1glox' to each side of the equation.
1a + glox + -1glox + 1x = 8 + -1glox

Combine like terms: glox + -1glox = 0
1a + 0 + 1x = 8 + -1glox
1a + 1x = 8 + -1glox

Add '-1x' to each side of the equation.
1a + 1x + -1x = 8 + -1glox + -1x

Combine like terms: 1x + -1x = 0
1a + 0 = 8 + -1glox + -1x
1a = 8 + -1glox + -1x

Divide each side by '1'.
a = 8 + -1glox + -1x

Simplifying
a = 8 + -1glox + -1x

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