logx(2x+3)+logx(x-2)=2

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Solution for logx(2x+3)+logx(x-2)=2 equation:


Simplifying
logx(2x + 3) + logx(x + -2) = 2

Reorder the terms:
glox(3 + 2x) + logx(x + -2) = 2
(3 * glox + 2x * glox) + logx(x + -2) = 2
(3glox + 2glox2) + logx(x + -2) = 2

Reorder the terms:
3glox + 2glox2 + glox(-2 + x) = 2
3glox + 2glox2 + (-2 * glox + x * glox) = 2
3glox + 2glox2 + (-2glox + glox2) = 2

Reorder the terms:
3glox + -2glox + 2glox2 + glox2 = 2

Combine like terms: 3glox + -2glox = 1glox
1glox + 2glox2 + glox2 = 2

Combine like terms: 2glox2 + glox2 = 3glox2
1glox + 3glox2 = 2

Solving
1glox + 3glox2 = 2

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-2 + 1glox + 3glox2 = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + 1glox + 3glox2 = 0

The solution to this equation could not be determined.

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