loge(x-1)+loge(x+2)=1

Solution for loge(x-1)+loge(x+2)=1 equation:

Simplifying
loge(x + -1) + loge(x + 2) = 1

Reorder the terms:
eglo(-1 + x) + loge(x + 2) = 1
(-1 * eglo + x * eglo) + loge(x + 2) = 1
(-1eglo + eglox) + loge(x + 2) = 1

Reorder the terms:
-1eglo + eglox + eglo(2 + x) = 1
-1eglo + eglox + (2 * eglo + x * eglo) = 1
-1eglo + eglox + (2eglo + eglox) = 1

Reorder the terms:
-1eglo + 2eglo + eglox + eglox = 1

Combine like terms: -1eglo + 2eglo = 1eglo
1eglo + eglox + eglox = 1

Combine like terms: eglox + eglox = 2eglox
1eglo + 2eglox = 1

Solving
1eglo + 2eglox = 1

Solving for variable 'e'.

Move all terms containing e to the left, all other terms to the right.

Reorder the terms:
-1 + 1eglo + 2eglox = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + 1eglo + 2eglox = 0

The solution to this equation could not be determined.