loge(x+1)+loge(x-1)=4

Solution for loge(x+1)+loge(x-1)=4 equation:

Simplifying
loge(x + 1) + loge(x + -1) = 4

Reorder the terms:
eglo(1 + x) + loge(x + -1) = 4
(1 * eglo + x * eglo) + loge(x + -1) = 4
(1eglo + eglox) + loge(x + -1) = 4

Reorder the terms:
1eglo + eglox + eglo(-1 + x) = 4
1eglo + eglox + (-1 * eglo + x * eglo) = 4
1eglo + eglox + (-1eglo + eglox) = 4

Reorder the terms:
1eglo + -1eglo + eglox + eglox = 4

Combine like terms: 1eglo + -1eglo = 0
0 + eglox + eglox = 4
eglox + eglox = 4

Combine like terms: eglox + eglox = 2eglox
2eglox = 4

Solving
2eglox = 4

Solving for variable 'e'.

Move all terms containing e to the left, all other terms to the right.

Divide each side by '2glox'.
e = 2g-1l-1o-1x-1

Simplifying
e = 2g-1l-1o-1x-1