loge(x)+loge(3x+4)=2loge(2)

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Solution for loge(x)+loge(3x+4)=2loge(2) equation:


Simplifying
loge(x) + loge(3x + 4) = 2loge(2)

Multiply eglo * x
eglox + loge(3x + 4) = 2loge(2)

Reorder the terms:
eglox + eglo(4 + 3x) = 2loge(2)
eglox + (4 * eglo + 3x * eglo) = 2loge(2)
eglox + (4eglo + 3eglox) = 2loge(2)

Reorder the terms:
4eglo + eglox + 3eglox = 2loge(2)

Combine like terms: eglox + 3eglox = 4eglox
4eglo + 4eglox = 2loge(2)

Reorder the terms for easier multiplication:
4eglo + 4eglox = 2 * 2eglo

Multiply 2 * 2
4eglo + 4eglox = 4eglo

Add '-4eglo' to each side of the equation.
4eglo + -4eglo + 4eglox = 4eglo + -4eglo

Combine like terms: 4eglo + -4eglo = 0
0 + 4eglox = 4eglo + -4eglo
4eglox = 4eglo + -4eglo

Combine like terms: 4eglo + -4eglo = 0
4eglox = 0

Solving
4eglox = 0

Solving for variable 'e'.

Move all terms containing e to the left, all other terms to the right.

Divide each side by '4'.
eglox = 0

Simplifying
eglox = 0

The solution to this equation could not be determined.

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