loge(2x+1)=2

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Solution for loge(2x+1)=2 equation: 


Simplifying
loge(2x + 1) = 2

Reorder the terms:
eglo(1 + 2x) = 2
(1 * eglo + 2x * eglo) = 2
(1eglo + 2eglox) = 2

Solving
1eglo + 2eglox = 2

Solving for variable 'e'.

Move all terms containing e to the left, all other terms to the right.

Reorder the terms:
-2 + 1eglo + 2eglox = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + 1eglo + 2eglox = 0

The solution to this equation could not be determined.

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